>well y gotta admit TADC is still better than most real womanslop out there. gooseworx seems to be based, she doesnt shove her trans identity down everyones throats and just lives her quiet life
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>Basic math? Very easy!

2 + 2 = 5
get it guys
Wrong.
70298 - SoyBooru.png
 
Let A be a matrix, not necessarily square. Say V and W are particular solutions
of the equations AV = Y1 and AW = Y2 , respectively, while Z 6 = 0 is a solution
of the homogeneous equation AZ = 0. Answer the following in terms of V , W , and
Z.

-Find some solution of AX = 3Y1 .


-Find some solution of AX = −5Y2 .


-Find some solution of AX = 3Y1 − 5Y2 .


-Find another solution (other than Z and 0) of the homogeneous equation AX = 0.


-Find two solutions of AX = Y1 .


-Find another solution of AX = 3Y1 − 5Y2 .


-If A is a square matrix, then det A =?


-If A is a square matrix, for any given vector W can one always find at least one
solution of AX = W ? Why?



 
Let A be a matrix, not necessarily square. Say V and W are particular solutions
of the equations AV = Y1 and AW = Y2 , respectively, while Z 6 = 0 is a solution
of the homogeneous equation AZ = 0. Answer the following in terms of V , W , and
Z.

-Find some solution of AX = 3Y1 .


-Find some solution of AX = −5Y2 .


-Find some solution of AX = 3Y1 − 5Y2 .


-Find another solution (other than Z and 0) of the homogeneous equation AX = 0.


-Find two solutions of AX = Y1 .


-Find another solution of AX = 3Y1 − 5Y2 .


-If A is a square matrix, then det A =?


-If A is a square matrix, for any given vector W can one always find at least one
solution of AX = W ? Why?



View attachment 27832
i got #4 place in a middle school math competition one time so this all makes sense to me really
 
Let A be a matrix, not necessarily square. Say V and W are particular solutions
of the equations AV = Y1 and AW = Y2 , respectively, while Z 6 = 0 is a solution
of the homogeneous equation AZ = 0. Answer the following in terms of V , W , and
Z.

-Find some solution of AX = 3Y1 .


-Find some solution of AX = −5Y2 .


-Find some solution of AX = 3Y1 − 5Y2 .


-Find another solution (other than Z and 0) of the homogeneous equation AX = 0.


-Find two solutions of AX = Y1 .


-Find another solution of AX = 3Y1 − 5Y2 .


-If A is a square matrix, then det A =?


-If A is a square matrix, for any given vector W can one always find at least one
solution of AX = W ? Why?



View attachment 27832
https://pomf2.lain.la/f/ii1a5ac.pdf
 
I never said this, I just solved your algebra 1 homework for you
I thought you linked the pdf i got the problem from. My bad my noob i never actually clicked the link.
135 - 71867a794e86033ca44725ff8c487e46.png
 
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